添加 py过滤
This commit is contained in:
commit
ae390a0ea3
20
py过滤
Normal file
20
py过滤
Normal file
@ -0,0 +1,20 @@
|
||||
#题目:怎么用推导式将下面这个列表中的元素遍历出来,只留下字母数字空格和花括号,并输出一个完整的字符串呢?
|
||||
# [["RℯℱE", "DR✍O", "CK{❦"], ["I a", "m le♫a", "rn†‡in"], ["g Py✣✤✥t", "ho⇒⇓⇔⇕na", "t SR々E}"]]
|
||||
#思路:先使用循环遍历出子列表、字符串、字符;使用isspace()、isalnum()判断是否为空格、数字或字符,最后输出result。注意:遍历每个字符过滤,而非字符串
|
||||
# 一步完成:展平嵌套结构 + 过滤特殊字符 + 拼接字符串
|
||||
|
||||
lst = [["RℯℱE", "DR✍O", "CK{❦"], ["I a", "m le♫a", "rn†‡in"], ["g Py✣✤✥t", "ho⇒⇓⇔⇕na", "t SR々E}"]]
|
||||
|
||||
|
||||
#join()是一个字符串方法,用于将可迭代对象中的元素连接为一个字符串
|
||||
#' '.join() 以空格来连接
|
||||
|
||||
result = ''.join(
|
||||
char for sublist in lst #生成器表达方式,遍历外层列表,char是接收最后用于输出的字符
|
||||
for s in sublist # 遍历每个子列表中的字符串
|
||||
for char in s # 遍历字符串的每个字符
|
||||
if char.isalnum() or char.isspace() or char in '{}'
|
||||
)
|
||||
print(result)
|
||||
|
||||
|
Loading…
x
Reference in New Issue
Block a user